Accuplacer Advanced Algebra and Functions Practice Exam 2025 - Free Advanced Algebra Practice Questions and Study Guide

Question: 1 / 400

Simplify \( \frac{4x^2 - 16}{2x - 4} \).

2(x + 2)

To simplify the expression \( \frac{4x^2 - 16}{2x - 4} \), we begin by factoring both the numerator and the denominator.

The numerator, \( 4x^2 - 16 \), can be recognized as a difference of squares. It can be factored as follows:

\[

4(x^2 - 4) = 4(x - 2)(x + 2)

\]

Next, the denominator \( 2x - 4 \) can be factored by taking out the common factor of 2:

\[

2(x - 2)

\]

Putting it all together, the original expression now looks like this:

\[

\frac{4(x - 2)(x + 2)}{2(x - 2)}

\]

We can now cancel the common factor \( (x - 2) \) from the numerator and the denominator, assuming \( x \neq 2 \) to avoid division by zero. This simplifies our expression to:

\[

\frac{4(x + 2)}{2}

\]

When we divide \( 4 \) by \( 2 \), we get \( 2 \). Therefore, the

Get further explanation with Examzify DeepDiveBeta

2(x + 4)

2(x - 4)

4(x + 4)

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